He Alex,
i talked to Sebastian (the phpunit creator) about that problem and yes: The argument gets clone
ed before it is passed to the callback.
From the top of my head i can't offer you any workaround but i choose to answer anyway to at least tell you that you are doing nothing wrong and that this is expected behavior.
To quote Sebastians comment on IRC on why it clones the argument:
It's a long-going debate between me, myself, and users of PHPUnit whether or not this is right ;-)
To have something copy/pasteable:
Assertion 3 in this codesample will fail. (The variable is only changed in the returned object)
<?php
class A
{
function foobar($o)
{
$o->x = mt_rand(5, 100);
}
}
class Test extends PHPUnit_Framework_TestCase
{
public function testFoo()
{
$mock = $this->getMock('A');
$mock->expects($this->any())
->method('foobar')
->will($this->returnCallback(function($o) { $o->x = 2; return $o; }));
$o = new StdClass;
$o->x = 1;
$this->assertEquals(1, $o->x);
$return = $mock->foobar($o);
$this->assertEquals(2, $return->x);
$this->assertEquals(2, $o->x);
}
}
Update:
Starting with PHPUnit 3.7 the cloning can be turned off. See the last argument off:
public function getMock(
$originalClassName,
$methods = array(),
array $arguments = array(),
$mockClassName = '',
$callOriginalConstructor = TRUE,
$callOriginalClone = TRUE,
$callAutoload = TRUE,
$cloneArguments = FALSE
);
It might even be off by default :)
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…