android - Create a ripple drawable without transparency

Question

I'm a bit lost about how to properly use Ripple Drawable.

Let's say I have this drawable :

<?xml version="1.0" encoding="utf-8"?>

<selector xmlns:android="http://schemas.android.com/apk/res/android" >
     <item android:state_pressed="false" android:state_focused="true" android:drawable="@color/accent_color_light" />
     <item android:state_pressed="true" android:drawable="@color/accent_color_light" />
     <item android:drawable="@android:color/white" />
</selector>

So it is a plain white background which changes to a light blue when it is focused or pressed.

How can I get the same colors but with a ripple effect ? I think I need to use a mask to prevent it from getting outside the bounds of the view ?

Answer 1

Forgot to answer my own question.

<?xml version="1.0" encoding="utf-8"?>
<ripple xmlns:android="http://schemas.android.com/apk/res/android"
   android:exitFadeDuration="@android:integer/config_shortAnimTime"
   android:color="@color/my_color" >

   <item android:id="@android:id/mask">
       <shape android:shape="rectangle" >
           <solid android:color="@android:color/holo_green_light" />
       </shape>
    </item>

</ripple>

The color in the item with the id "mask" is not displayed. It is used to tell the shape and bounds of the ripple effect. Without it, it can go outside the bounds of the view.