Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
4.7k views
in Technique[技术] by (71.8m points)

R: Split dataframe into columns and recombine to rows

Trying my very best for several hours now and hope someone can help me with the following.

The dataset I load into R looks like this (with many many more replications)

enter image description here

My output should look like that:

enter image description here

split.default(Mydata, rep(1:3, each = 5)) did the job in splitting the data frame into columns but I then do not know how to a) add the Replication column and b) how to combine the different tibbles into a single dataframe.

Thanks for your help in advance!

Data:

structure(list(Replication1 = c("Timestamp", "44046", "44046.02884259259", 
"44046.065949074073", "44046.088472222225", "44046.0934837963", 
"44046.105208333334", "44046.115613425929", "44046.35355324074", 
"44046.419537037036", "44046", "44046.02884259259", "44046.065949074073", 
"44046.088472222225", "44046.0934837963", "44046.105208333334", 
"44046.115613425929", "44046.35355324074", "44046.419537037036", 
"44049.058587962965", "44049.08630787037", "44049.184525462966", 
"44049.188009259262", "44049.28429398148", "44049.373472222222", 
"44049.464212962965", "44049.472627314812"), ...2 = c("a", "0", 
"0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
"0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0"), 
    ...3 = c("b", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0"), ...4 = c("c", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "0", "37", "37", "37", "37", "37", "37", "37", "37"), 
    ...5 = c("d", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", "0", "20", "20", 
    "20", "20", "20", "20", "20", "20"), Replication2 = c("Timestamp", 
    "44046", "44046.02884259259", "44046.065949074073", "44046.088472222225", 
    "44046.0934837963", "44046.105208333334", "44046.115613425929", 
    "44046.35355324074", "44046.419537037036", "44049.058587962965", 
    "44049.08630787037", "44049.184525462966", "44049.188009259262", 
    "44049.28429398148", "44049.373472222222", "44049.464212962965", 
    "44049.472627314812", NA, NA, NA, NA, NA, NA, NA, NA, NA), 
    ...7 = c("a", "0", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", NA, NA, NA, NA, NA, 
    NA, NA, NA, NA), ...8 = c("b", "0", "0", "0", "0", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", "0", NA, 
    NA, NA, NA, NA, NA, NA, NA, NA), ...9 = c("c", "0", "0", 
    "0", "0", "0", "0", "0", "0", "0", "37", "37", "37", "37", 
    "37", "37", "37", "37", NA, NA, NA, NA, NA, NA, NA, NA, NA
    ), ...10 = c("d", "0", "0", "0", "0", "0", "0", "0", "0", 
    "0", "20", "20", "20", "20", "20", "20", "20", "20", NA, 
    NA, NA, NA, NA, NA, NA, NA, NA), Replication3 = c("Timestamp", 
    "44094.918553240743", "44094.960196759261", "44094.960393518515", 
    "44095.006030092591", "44095.259652777779", "44095.275034722225", 
    "44095.31045138889", "44095.323263888888", "44095.386574074073", 
    "44095.425659722219", NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA), ...12 = c("a", "1", "1", "1", 
    "1", "2", "2", "2", "2", "2", "2", NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), ...13 = c("b", "0", 
    "0", "0", "0", "0", "0", "0", "0", "0", "0", NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), ...14 = c("c", 
    "37", "37", "37", "37", "37", "37", "37", "37", "37", "37", 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    NA), ...15 = c("d", "20", "20", "20", "20", "20", "20", "20", 
    "20", "20", "20", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA)), row.names = c(NA, -27L), class = c("tbl_df", 
"tbl", "data.frame"))

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Try this brute force approach with a loop. We can detect the position of key variables to determine a start/end path and then use the loop to format the data. Finally, we bind the results using do.call() and rbind():

#Code
index <- which(grepl('Replication',names(Mydata)))
index2 <- index[-1]
index2 <- index2-1
index2 <- c(index2,dim(Mydata)[2])
#List
List <- list()
#Loop
for(i in 1:length(index))
{
  df <- Mydata[,(index[i]:index2[i])]
  val <- names(df)[1]
  colnames(df) <- df[1,]
  df <- df[-1,]
  df$Replicate <- val
  List[[i]] <- df
}
#Bind
mdf <- do.call(rbind,List)

Output:

mdf
# A tibble: 78 x 6
   Timestamp          a     b     c     d     Replicate   
   <chr>              <chr> <chr> <chr> <chr> <chr>       
 1 44046              0     0     0     0     Replication1
 2 44046.02884259259  0     0     0     0     Replication1
 3 44046.065949074073 0     0     0     0     Replication1
 4 44046.088472222225 0     0     0     0     Replication1
 5 44046.0934837963   0     0     0     0     Replication1
 6 44046.105208333334 0     0     0     0     Replication1
 7 44046.115613425929 0     0     0     0     Replication1
 8 44046.35355324074  0     0     0     0     Replication1
 9 44046.419537037036 0     0     0     0     Replication1
10 44046              0     0     0     0     Replication1
# ... with 68 more rows

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...