There are a few ways to achieve this, one would be to group the results and use HAVING
to compare the count of the distinct tags
$query = $this->Users
->find()
->matching('Tags', function ($query) {
return $query->where(['Tags.name IN' => ['Tag1', 'Tag2']]);
})
->group('Users.id')
->having([
$this->Users->query()->newExpr('COUNT(DISTINCT Tags.name) = 2')
]);
This will select only those users that have two distinct tags, which can only be Tag1
and Tag2
since these are the only ones that are being joined in. In case the name
column is unique, you may count on the primary key instead.
The IN
btw. is essentially the same as your OR
conditions (the database system will expand IN
to OR
conditions accordingly).
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