Examples:
char test1[] = " ";
char test2[] = " hello z";
char test3[] = "hello world ";
char test4[] = "x y z ";
Results:
" "
" olleh z"
"olleh dlrow "
"x y z "
The problem:
Reverse every world in a string, ignore the spaces.
The following is my code. The basic idea is to scan the string, when
finding a word, then reverse it. The complexity of the algorithm is
O(n), where n is the length of the string.
How do verify it? Is there a better solution?
void reverse_word(char* s, char* e)
{
while (s < e)
{
char tmp = *s;
*s = *e;
*e = tmp;
++s;
--e;
}
}
char* word_start_index(char* p)
{
while ((*p != '') && (*p == ' '))
{
++p;
}
if (*p == '')
return NULL;
else
return p;
}
char* word_end_index(char* p)
{
while ((*p != '') && (*p != ' '))
{
++p;
}
return p-1;
}
void reverse_string(char* s)
{
char* s_w = NULL;
char* e_w = NULL;
char* runner = s;
while (*runner != '')
{
char* cur_word_s = word_start_index(runner);
if (cur_word_s == NULL)
break;
char* cur_word_e = word_end_index(cur_word_s);
reverse_word(cur_word_s, cur_word_e);
runner = cur_word_e+1;
}
}
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