c++ - OpenCV : convert the pointer in memory to image

Question

I have a grabber which can get the images and show them on the screen with the following code

while((lastPicNr = Fg_getLastPicNumberBlockingEx(fg,lastPicNr+1,0,10,_memoryAllc))<200) {                                                           
                iPtr=(unsigned char*)Fg_getImagePtrEx(fg,lastPicNr,0,_memoryAllc);                  
                ::DrawBuffer(nId,iPtr,lastPicNr,"testing");                                         }

but I want to use the pointer to the image data and display them with OpenCV, cause I need to do the processing on the pixels. my camera is a CCD mono camera and the depth of the pixels is 8bits. I am new to OpenCV, is there any option in opencv that can get the return of the (unsigned char*)Fg_getImagePtrEx(fg,lastPicNr,0,_memoryAllc); and disply it on the screen? or get the data from the iPtr pointer an allow me to use the image data?

Answer 1

Creating an IplImage from unsigned char* raw_data takes 2 important instructions: cvCreateImageHeader() and cvSetData():

// 1 channel for mono camera, and for RGB would be 3
int channels = 1; 
IplImage* cv_image = cvCreateImageHeader(cvSize(width,height), IPL_DEPTH_8U, channels);
if (!cv_image)
{
    // print error, failed to allocate image!
}

cvSetData(cv_image, raw_data, cv_image->widthStep);

cvNamedWindow("win1", CV_WINDOW_AUTOSIZE);
cvShowImage("win1", cv_image);
cvWaitKey(10);

// release resources
cvReleaseImageHeader(&cv_image);
cvDestroyWindow("win1");

I haven't tested the code, but the roadmap for the code you are looking for is there.