Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
305 views
in Technique[技术] by (71.8m points)

ios - UDID Replacement in IOS7

Is there is a alternative for UDID. My app will not be going to App Store as i'm using enterprise distribution. So is there any replacement. I tied advertising identifier, open udid, UIID and secure UDID. But if the phone is reset then i will get a new UDID. Any help would be appreciated.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

For above 6.0 iOS you can use identifierForVendor Or CFUUIDRef.

-(NSString*)uniqID
{
    NSString* uniqueIdentifier = nil;
    if( [UIDevice instancesRespondToSelector:@selector(identifierForVendor)] ) {
        // iOS 6+
        uniqueIdentifier = [[[UIDevice currentDevice] identifierForVendor] UUIDString];
    } else {
        // before iOS 6, so just generate an identifier and store it
        uniqueIdentifier = [[NSUserDefaults standardUserDefaults] objectForKey:@"identifierForVendor"];
        if( !uniqueIdentifier ) {
            CFUUIDRef uuid = CFUUIDCreate(NULL);
            uniqueIdentifier = ( NSString*)CFUUIDCreateString(NULL, uuid);
            CFRelease(uuid);
            [[NSUserDefaults standardUserDefaults] setObject:uniqueIdentifier forKey:@"identifierForVendor"];
        }
    }
return uniqueIdentifier;
}//

UPDATE

As Leon Lucardie comment he is right

identifierForVendor will change after app uninstall/reinstall. See here The value in this property remains the same while the app (or another app from the same vendor) is installed on the iOS device. The value changes when the user deletes all of that vendor’s apps from the device and subsequently reinstalls one or more of them.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...