node.js - sequelize findAll sort order in nodejs

Question

I'm trying to output all object list from database with sequelize as follow and want to get data are sorted out as I added id in where clause.

exports.getStaticCompanies = function () {
    return Company.findAll({
        where: {
            id: [46128, 2865, 49569,  1488,   45600,   61991,  1418,  61919,   53326,   61680]
        },
        attributes: ['id', 'logo_version', 'logo_content_type', 'name', 'updated_at']
    });
};

But the problem is after rendering, all data are sorted out as follow.

46128, 53326, 2865, 1488, 45600, 61680, 49569, 1418, ....

As I found, it's neither sorted by id nor name. Please help me how to solve it.

Answer 1

In sequelize you can easily add order by clauses.

exports.getStaticCompanies = function () {
    return Company.findAll({
        where: {
            id: [46128, 2865, 49569,  1488,   45600,   61991,  1418,  61919,   53326,   61680]
        }, 
        // Add order conditions here....
        order: [
            ['id', 'DESC'],
            ['name', 'ASC'],
        ],
        attributes: ['id', 'logo_version', 'logo_content_type', 'name', 'updated_at']
    });
};

See how I've added the order array of objects?

order: [
      ['COLUMN_NAME_EXAMPLE', 'ASC'], // Sorts by COLUMN_NAME_EXAMPLE in ascending order
],

Edit:

You might have to order the objects once they've been recieved inside the .then() promise. Checkout this question about ordering an array of objects based on a custom order:

How do I sort an array of objects based on the ordering of another array?