new operator - How to initialize members in Go struct

Question

I am new to Golang so allocation in it makes me insane:

import "sync"

type SyncMap struct {
        lock *sync.RWMutex
        hm map[string]string
}
func (m *SyncMap) Put (k, v string) {
        m.lock.Lock()
        defer m.lock.Unlock()

        m.hm[k] = v, true
}

and later, I just call:

sm := new(SyncMap)
sm.Put("Test, "Test")

At this moment I get a nil pointer panic.

I've worked around it by using another one function, and calling it right after new():

func (m *SyncMap) Init() {
        m.hm = make(map[string]string)
        m.lock = new(sync.RWMutex)
}

But I wonder, if it's possible to get rid of this boilerplate initializing?

Answer 1

Waitting for answers