Sometimes you need a Makefile to be able to run on different target OS's and you want the build to fail early if a required executable is not in PATH
rather than to run for a possibly long time before failing.
The excellent solution provided by engineerchuan requires making a target. However, if you have many executables to test and your Makefile has many independent targets, each of which requires the tests, then each target requires the test target as a dependency. That makes for a lot of extra typing as well as processing time when you make more than one target at a time.
The solution provided by 0xf can test for an executable without making a target. That saves a lot of typing and execution time when there are multiple targets that can be built either separately or together.
My improvement to the latter solution is to use the which
executable (where
in Windows), rather than to rely on there being a --version
option in each executable, directly in the GNU Make ifeq
directive, rather than to define a new variable, and to use the GNU Make error
function to stop the build if a required executable is not in ${PATH}
. For example, to test for the lzop
executable:
ifeq (, $(shell which lzop))
$(error "No lzop in $(PATH), consider doing apt-get install lzop")
endif
If you have several executables to check, then you might want to use a foreach
function with the which
executable:
EXECUTABLES = ls dd dudu lxop
K := $(foreach exec,$(EXECUTABLES),
$(if $(shell which $(exec)),some string,$(error "No $(exec) in PATH")))
Note the use of the :=
assignment operator that is required in order to force immediate evaluation of the RHS expression. If your Makefile changes the PATH
, then instead of the last line above you will need:
$(if $(shell PATH=$(PATH) which $(exec)),some string,$(error "No $(exec) in PATH")))
This should give you output similar to:
ads$ make
Makefile:5: *** "No dudu in PATH. Stop.
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