its a simple code. I want to keep a record in the database each time when a file is being uploaded. And when each time any file is being uploaded I want the user to see he/her's all uploaded files in a serial from the database. The record keeping while uploading file works fine. But the problem appears while fetching the table containing all the uploaded file information.
//connetion code
$con = mysqli_connect("localhost", "root", "", "sss");
if (mysqli_connect_errno())
{
printf("Connect failed: %s
", mysqli_connect_error());
exit();
}
//file upload code
move_uploaded_file($_FILES["file"]["tmp_name"],"C:/xampp/htdocs/" . $_FILES["file"]["name"]);
mysqli_query($con, "INSERT INTO uploads ( filename, uploaded_on) VALUES ( '{$_FILES['file']['name']}', NOW());");
echo "Stored in: " . "C:/xampp/htdocs/" . $_FILES["file"]["name"];
//fetch rows
$result =mysqli_query($con, "select * from uploads");
while ($row = mysqli_fetch_array($result))
{
printf ("%s
", $row);
}
mysqli_close($con);
}
I can feel that there are some serious problem in coding. This is my first time working in mysqli, before I used to code using mysql. need help to know the actual problem and the solution.
Edited:
it returns this,
Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
Array
Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
Array
Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
Array
but unfortunately this code is a part of a huge code. so here line 68 is the line where the $result = mysqli_query($con, "select * from uploads");
starts.
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