string - Printing C++ int pointer vs char pointer

Question

When I run the following code:

int i[] = {1,2,3};
int* pointer = i;
cout << i << endl;

char c[] = {'a','b','c',''};
char* ptr = c;
cout << ptr << endl;

I get this output:

0x28ff1c
abc

Why does the int pointer return the address while the char pointer returns the actual content of the array?

Answer 1

This is due to overload of << operator. For char * it interprets it as null terminated C string. For int pointer, you just get the address.