macos - "echo -n" works fine when executing script with bash, but not with sh

Question

How come sh UsersInput.sh gives a different output compared to bash UsersInput.sh?

My script is below:

#!/bin/bash
echo -n "Enter: ";
read usersinput;
echo "You entered, "$usersinput""; 

bash

localhost:Bash henry$ bash UsersInput.sh 
Enter: input
You entered, "input"

sh

localhost:Bash henry$ sh UsersInput.sh
-n Enter: 
input
You entered, "input"

How come -n behaves properly with the first, but not with the second? What's the reason for this and is there a workaround?

Answer 1

From man echo:

Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does not accept the -n option. Consult the builtin(1) manual page.

In bash, the Bourne-again shell, echo accepts the -n option whereas in sh, the Bourne shell, echo does not, so it simply echos everything you wrote, including the -n.