printing - Print text between delimiters using sed

Question

Suppose I have op(abc)asdfasdf and I need sed to print abc between the brackets. What would work for me? (Note: I only want the text between first pair of delimiters on a line, and nothing if a particular line of input does not have a pair of brackets.)

Answer 1

$ echo 'op(abc)asdfasdf' | sed 's|[^(]*(([^)]*)).*|1|'
abc