xslt - Making JAXB generate an XML processing instruction

Question

I am generating XML dynamically using JAXB.

Now, I want to convert it to HTML using XSL. How can i include

<?xml-stylesheet type="text/xsl" href=""> 

in the dynamically generated XML?

Answer 1

All the solutions here are pretty ugly and verbose. Simply set the line inside the Mashaller object specifying the additional header.

Marshaller jaxbMarshaller = ...
jaxbMarshaller.setProperty("com.sun.xml.bind.xmlHeaders", 
    "<?xml-stylesheet type='text/xsl' href='nameoffile.xsl' ?>");

This example will output an XML object to a file using a stylesheet and format the elements nicely for humans to read. The object myXmlObject is of class MyXmlClass, and will be written to file, formatted by a stylesheet given by xslUrl:

JAXBContext context = JAXBContext.newInstance(MyXmlClass.class);
Marshaller marshaller = context.createMarshaller();
//Need to use a Writer to marshal with the XSL
FileWriter fw = new FileWriter(file);
//Do this or else the XML is all one line and not human friendly...
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
marshaller.setProperty("com.sun.xml.bind.xmlHeaders",
        "<?xml-stylesheet type='text/xsl' href="" +
        xslUrl +
        "" ?>");
marshaller.marshal(myXmlObject, fw);

---

Update

In recent version of JAXB we need to use property key as com.sun.xml.internal.bind.xmlHeaders like below.

Marshaller jaxbMarshaller = ...
jaxbMarshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders", 
    "<?xml-stylesheet type='text/xsl' href='nameoffile.xsl' ?>");