Just to get it straight in my head. Consider this example bit of Erlang code:
test() ->
receive
{From, whatever} ->
%% do something
test();
{From, somethingelse} ->
%% do something else
test();
end.
Isn't the test() call, just a goto?
I ask this because in C we learned, if you do a function call, the return location is always put on the stack. I can't imagine this must be the case in Erlang here since this would result in a stackoverflow.
We had 2 different ways of calling functions:
goto and gosub.
goto just steered the program flow somewhere else, and gosub remembered where you came from so you could return.
Given this way of thinking, I can look at Erlang's recursion easier, since if I just read: test() as a goto, then there is no problem at all.
hence my question: isn't :Erlang just using a goto instead of remembering the return address on a stack?
EDIT:
Just to clarify my point:
I know goto's can be used in some languages to jump all over the place. But just supose instead of doing someFunction() you can also do: goto someFunction()
in the first example the flow returns, in the second example the flow just continues in someFunction and never returns.
So we limit the normal GOTO behaviour by just being able to jump to method starting points.
If you see it like this, than the Erlang recursive function call looks like a goto.
(a goto in my opinion is a function call without the ability to return where you came from). Which is exactly what is happening in the Erlang example.
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