I am studying encryption. And I got a problem like this:
After I XOR plaintext with a key, I get a crypt, "010e010c15061b4117030f54060e54040e0642181b17", as hex type. If I want to get plaintext from this crypt, what should I do in PHP?
I tried convert it to string/int and after that take them to XOR with the key (three letters). But it doesn't work.
This is the code:
function xor_this($string) {
// Let's define our key here
$key = 'fpt';
// Our plaintext/ciphertext
$text = $string;
// Our output text
$outText = '';
// Iterate through each character
for($i=0; $i<strlen($text); )
{
for($j=0; $j<strlen($key); $j++,$i++)
{
$outText .= ($text[$i] ^ $key[$j]);
//echo 'i=' . $i . ', ' . 'j=' . $j . ', ' . $outText{$i} . '<br />'; // For debugging
}
}
return $outText;
}
function strToHex($string)
{
$hex = '';
for ($i=0; $i < strlen($string); $i++)
{
$hex .= dechex(ord($string[$i]));
}
return $hex;
}
function hexToStr($hex)
{
$string = '';
for ($i=0; $i < strlen($hex)-1; $i+=2)
{
$string .= chr(hexdec($hex[$i].$hex[$i+1]));
}
return $string;
}
$a = "This is the test";
$b = xor_this($a);
echo xor_this($b), '-------------';
//
$c = strToHex($b);
$e = xor_this($c);
echo $e, '++++++++';
//
$d = hexToStr($c);
$f = xor_this($d);
echo $f, '=================';
And this is the result:
This is the test-------------
PHP Notice: Uninitialized string offset: 29 in C:
UsersAdministratorDesktopest.php on line 210 PHP Stack trace: PHP
1. {main}() C:UsersAdministratorDesktopest.php:0 PHP 2. xor_this() C:UsersAdministratorDesktopest.php:239
Notice: Uninitialized string offset: 29 in
C:UsersAdministratorDesktopest.p hp on line 210
Call Stack:
0.0005 674280 1. {main}() C:UsersAdministratorDesktopest.php:0
0.0022 674848 2. xor_this() C:UsersAdministratorDesktopest.php:23 9
UBE^A?WEAVA?WEAV@?WEARAFWECWB++++++++
This is zs$fs?=================
Why? The "UBE^A?WEAVA?WEAV@?WEARAFWECWB++++++++" is the result, which I got trouble in my real work.
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