First, K&R have an errata on this particular snippet:
117(§5.10): In the find example, the program increments argv[0]
. This is not specifically forbidden, but not specifically allowed either.
Now for the explanation.
Let's say your program is named prog
, and you execute it with: prog -ab -c Hello World
. You want to be able to parse the arguments to say that options a
, b
and c
were specified, and Hello
and World
are the non-option arguments.
argv
is of type char **
—remember that an array parameter in a function is the same as a pointer. At program invocation, things look like this:
+---+ +---+---+---+---+---+
argv ---------->| 0 |-------->| p | r | o | g | 0 |
+---+ +---+---+---+---+---+
| 1 |-------->| - | a | b | 0 |
+---+ +---+---+---+---+
| 2 |-------->| - | c | 0 |
+---+ +---+---+---+---+---+---+
| 3 |-------->| H | e | l | l | o | 0 |
+---+ +---+---+---+---+---+---+
| 4 |-------->| W | o | r | l | d | 0 |
+---+ +---+---+---+---+---+---+
| 5 |-------->NULL
+---+
Here, argc
is 5, and argv[argc]
is NULL
. At the beginning, argv[0]
is a char *
containing the string "prog"
.
In (*++argv)[0]
, because of the parentheses, argv
is incremented first, and then dereferenced. The effect of the increment is to move that argv ---------->
arrow "one block down", to point to the 1
. The effect of dereferencing is to get a pointer to the first commandline argument, -ab
. Finally, we take the first character ([0]
in (*++argv)[0]
) of this string, and test it to see if it is '-'
, because that denotes the start of an option.
For the second construct, we actually want to walk down the string pointed to by the current argv[0]
pointer. So, we need to treat argv[0]
as a pointer, ignore its first character (that is '-'
as we just tested), and look at the other characters:
++(argv[0])
will increment argv[0]
, to get a pointer to the first non- -
character, and dereferencing it will give us the value of that character. So we get *++(argv[0])
. But since in C, []
binds more tightly than ++
, we can actually get rid of the parentheses and get our expression as *++argv[0]
. We want to continue processing this character until it's 0
(the last character box in each of the rows in the above picture).
The expression
c = *++argv[0]
assigns to c
the value of the current option, and has the value c
. while(c)
is a shorthand for while(c != 0)
, so the while(c = *++argv[0])
line is basically assigning the value of the current option to c
and testing it to see if we have reached the end of the current command-line argument.
At the end of this loop, argv will point to the first non-option argument:
+---+ +---+---+---+---+---+
| 0 |-------->| p | r | o | g | 0 |
+---+ +---+---+---+---+---+
| 1 |-------->| - | a | b | 0 |
+---+ +---+---+---+---+
| 2 |-------->| - | c | 0 |
+---+ +---+---+---+---+---+---+
argv ---------->| 3 |-------->| H | e | l | l | o | 0 |
+---+ +---+---+---+---+---+---+
| 4 |-------->| W | o | r | l | d | 0 |
+---+ +---+---+---+---+---+---+
| 5 |-------->NULL
+---+
Does this help?