I have the following python script and it works beautifully.
import urllib2
url = 'http://abc.com' # write the url here
usock = urllib2.urlopen(url)
data = usock.read()
usock.close()
print data
however, some of the URL's I give it may redirect it 2 or more times. How can I have python wait for redirects to complete before loading the data.
For instance when using the above code with
http://www.google.com/search?hl=en&q=KEYWORD&btnI=1
which is the equvilant of hitting the im lucky button on a google search, I get:
>>> url = 'http://www.google.com/search?hl=en&q=KEYWORD&btnI=1'
>>> usick = urllib2.urlopen(url)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 438, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
>>>
Ive tried the (url, data, timeout) however, I am unsure what to put there.
EDIT:
I actually found out if I dont redirect and just used the header of the first link, I can grab the location of the next redirect and use that as my final link
See Question&Answers more detail:
os