Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
477 views
in Technique[技术] by (71.8m points)

recursion - Big O of Recursive Methods

I'm having difficulty determining the big O of simple recursive methods. I can't wrap my head around what happens when a method is called multiple times. I would be more specific about my areas of confusion, but at the moment I'm trying to answer some hw questions, and in lieu of not wanting to cheat, I ask that anyone responding to this post come up with a simple recursive method and provide a simple explanation of the big O of said method. (Preferably in Java... a language I'm learning.)

Thank you.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can define the order recursively as well. For instance, let's say you have a function f. To calculate f(n) takes k steps. Now you want to calculate f(n+1). Lets say f(n+1) calls f(n) once, then f(n+1) takes k + some constant steps. Each invocation will take some constant steps extra, so this method is O(n).

Now look at another example. Lets say you implement fibonacci naively by adding the two previous results:

fib(n) = { return fib(n-1) + fib(n-2) }

Now lets say you can calculate fib(n-2) and fib(n-1) both in about k steps. To calculate fib(n) you need k+k = 2*k steps. Now lets say you want to calculate fib(n+1). So you need twice as much steps as for fib(n-1). So this seems to be O(2^N)

Admittedly, this is not very formal, but hopefully this way you can get a bit of a feel.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...