bash - Parse HTML using shell

Question

I have a HTML with lots of data and part I am interested in:

<tr valign=top>
<td><b>Total</b></td>
<td align=right><b>54</b></td>
<td align=right><b>1</b></td>
<td align=right>0 (0/0)</td>
<td align=right><b>0</b></td>
</tr>

I try to use awk which now is:

awk -F "</*b>|</td>" '/<[b]>.*[0-9]/ {print $1, $2, $3 }' "index.html"

but what I want is to have:

54
1
0
0

Right now I am getting:

'<td align=right> 54'
'<td align=right> 1'
'<td align=right> 0'

Any suggestions?

Answer 1

awk is not an HTML parser. Use xpath or even xslt for that. xmllint is a commandline tool which is able to execute XPath queries and xsltproc can be used to perform XSL transformations. Both tools belong to the package libxml2-utils.

Also you can use a programming language which is able to parse HTML