Below is a form:
<form action="/example/html5/demo_form.asp" method="post"
enctype=”multipart/form-data”>
<input type="file" name="img" />
<input type="text" name=username" value="foo"/>
<input type="submit" />
</form>
when will submit this form, the request will look like this:
POST /example/html5/demo_form.asp HTTP/1.1
Host: 10.143.47.59:9093
Connection: keep-alive
Content-Length: 326
Accept: application/json, text/javascript, */*; q=0.01
Origin: http://10.143.47.59:9093
X-Requested-With: XMLHttpRequest
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.90 Safari/537.36
Content-Type: multipart/form-data; boundary=----WebKitFormBoundaryEDKBhMZFowP9Leno
Accept-Encoding: gzip, deflate
Accept-Language: en-US,en;q=0.8,zh-CN;q=0.6,zh;q=0.4
Request Payload
------WebKitFormBoundaryEDKBhMZFowP9Leno
Content-Disposition: form-data; name="username"
foo
------WebKitFormBoundaryEDKBhMZFowP9Leno
Content-Disposition: form-data; name="img"; filename="out.txt"
Content-Type: text/plain
------WebKitFormBoundaryEDKBhMZFowP9Leno--
please pay attention to the "Request Payload", you can see the two params in the form, the username and the img(form-data; name="img"; filename="out.txt"), and the finename is the real file name(or path) in your filesystem, you will receive the file by name(not filename) in your backend(such as spring controller).
if we use Apache Httpclient to simulate the request, we will write such code:
MultipartEntity mutiEntity = newMultipartEntity();
File file = new File("/path/to/your/file");
mutiEntity.addPart("username",new StringBody("foo", Charset.forName("utf-8")));
mutiEntity.addPart("img", newFileBody(file)); //img is name, file is path
But in java 9, We could write such code:
HttpClient client = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.
newBuilder(new URI("http:///example/html5/demo_form.asp"))
.method("post",HttpRequest.BodyProcessor.fromString("foo"))
.method("post", HttpRequest.BodyProcessor.fromFile(Paths.get("/path/to/your/file")))
.build();
HttpResponse response = client.send(request, HttpResponse.BodyHandler.asString());
System.out.println(response.body());
Now you see, how could I set the "name" of the param?
See Question&Answers more detail:
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