Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
760 views
in Technique[技术] by (71.8m points)

bash script, create array of all files in a directory

I have a directory myDir of many .html files. I am trying to create an array of all the files in the directory so I might be able to index the array and be able to refer to particular html files in the directory. I have tried the following line:

myFileNames=$(ls ~/myDir)

for file in $myFileNames; 
#do something

but I want to be able to have a counter variable and have logic like the following:

 while $counter>=0;
   #do something to myFileNames[counter]

I am quite new to shell scripting and am unable to figure out how to achieve this hence would appreciate any help regarding this matter.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can do:

# use nullglob in case there are no matching files
shopt -s nullglob

# create an array with all the filer/dir inside ~/myDir
arr=(~/myDir/*)

# iterate through array using a counter
for ((i=0; i<${#arr[@]}; i++)); do
    #do something to each element of array
    echo "${arr[$i]}"
done

You can also do this for iteration of array:

for f in "${arr[@]}"; do
   echo "$f"
done

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...