shell - Unix ls command: show full path when using options

Question

I often use this list command in Unix (AIX / KSH):

ls -Artl

It displays the files as this:

-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test1.txt
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test2.txt

I would like to modify the command such a way that the full path of the file is displayed. For example:

-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test1.txt
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test2.txt

Any ideas?

I found several resolution methods using pwd or find but - as far as I see - this does not work work if I want to keep the ls options.

Answer 1

What about this trick...

ls -lrt -d -1 $PWD/{*,.*}

OR

ls -lrt -d -1 $PWD/*

I think this has problems with empty directories but if another poster has a tweak I'll update my answer. Also, you may already know this but this is probably be a good candidate for an alias given it's lengthiness.

[update] added some tweaks based on comments, thanks guys.

[update] as pointed out by the comments you may need to tweek the matcher expressions depending on the shell (bash vs zsh). I've re-added my older command for reference.