shell - Bash glob parameter only shows first file instead of all files

Question

I want to run this cmd line script

$ script.sh   lib/* ../test_git_thing

I want it to process all the files in the /lib folder.

FILES=$1
for f in $FILES
do
  echo "Processing $f file..."
done

Currently it only prints the first file. If I use $@, it gives me all the files, but also the last param which I don't want. Any thoughts?

Answer 1

The argument list is being expanded at the command line when you invoke "script.sh lib/*" your script is being called with all the files in lib/ as args. Since you only reference $1 in your script, it's only printing the first file. You need to escape the wildcard on the command line so it's passed to your script to perform the globbing.