Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
808 views
in Technique[技术] by (71.8m points)

apache spark - GraphX - Retrieving all nodes from a path

In GraphX, is there a way to retrieve all the nodes and edges that are on a path that are of a certain length?

More specifically, I would like to get all the 10-step paths from A to B. For each path, I would like to get the list of nodes and edges.

Thanks.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Disclaimer: This is only intended to show GraphFrames path filtering capabilities.

Well, theoretically speaking it is possible. You can use GraphFrames patterns to find paths. Lets assume your data looks as follows:

import org.graphframes.GraphFrame

val nodes = "abcdefghij".map(c =>Tuple1(c.toString)).toDF("id")

val edges = Seq(
   // Long path
  ("a", "b"), ("b", "c"), ("c", "d"),  ("d", "e"), ("e", "f"),
  // and some random nodes
  ("g", "h"), ("i", "j"), ("j", "i")
).toDF("src", "dst")

val gf = GraphFrame(nodes, edges)

and you want to find all paths with at least 5 nodes.

You can construct following path pattern:

val path = (1 to 4).map(i => s"(n$i)-[e$i]->(n${i + 1})").mkString(";")
// (n1)-[e1]->(n2);(n2)-[e2]->(n3);(n3)-[e3]->(n4);(n4)-[e4]->(n5)

and filter expression to avoid cycles:

val expr = (1 to 5).map(i => s"n$i").combinations(2).map {
  case Seq(i, j) => col(i) !== col(j)
}.reduce(_ && _)

Finally quick check:

gf.find(path).where(expr).show
// +-----+---+---+-----+---+-----+---+-----+---+
// |   e1| n1| n2|   e2| n3|   e3| n4|   e4| n5|
// +-----+---+---+-----+---+-----+---+-----+---+
// |[a,b]|[a]|[b]|[b,c]|[c]|[c,d]|[d]|[d,e]|[e]|
// |[b,c]|[b]|[c]|[c,d]|[d]|[d,e]|[e]|[e,f]|[f]|
// +-----+---+---+-----+---+-----+---+-----+---+

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...