regex for access log in hive serde

Question

I want to extract out (ip, requestUrl, timeStamp) from the access logs to load to hive database. One line from access log is as follows.

66.249.68.6 - - [14/Jan/2012:06:25:03 -0800] "GET /example.com HTTP/1.1" 200 708 "-" "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)"

I tried with following and several variations of regex without any success. (The loaded table is with all NULL values indicating the regex doesn't match the input).

CREATE TABLE access_log (
  remote_ip STRING,
  request_date STRING,
  method STRING,
  request STRING,
  protocol STRING
)
ROW FORMAT SERDE 'org.apache.hadoop.hive.contrib.serde2.RegexSerDe'
WITH SERDEPROPERTIES  (
"input.regex" = "([^ ]) . . [([^]]+)] "([^ ]) ([^ ]) ([^ "])" *",
"output.format.string" = "%1$s %2$s %3$s %4$s %5$s"
)
STORED AS TEXTFILE;

I am not very experienced with regex. Can anybody help me with this?

Answer 1

Use double '' and '.*' in the end (it's important!):

CREATE EXTERNAL TABLE access_log (
        `ip`                STRING,
        `time_local`        STRING,
        `method`            STRING,
        `uri`               STRING,
        `protocol`          STRING,
        `status`            STRING,
        `bytes_sent`        STRING,
        `referer`           STRING,
        `useragent`         STRING
        )
    ROW FORMAT SERDE 'org.apache.hadoop.hive.contrib.serde2.RegexSerDe'
    WITH SERDEPROPERTIES (
    'input.regex'='^(\S+) \S+ \S+ \[([^\[]+)\] "(\w+) (\S+) (\S+)" (\d+) (\d+) "([^"]+)" "([^"]+)".*'
)
STORED AS TEXTFILE
LOCATION '/tmp/access_logs/';

P.S. Hive 0.7.1