formatting - Convert an amount to Indian Notation in Python

Question

Problem: I need to convert an amount to Indian currency format

My code: I have the following Python implementation:

import decimal
def currencyInIndiaFormat(n):
  d = decimal.Decimal(str(n))
  if d.as_tuple().exponent < -2:
    s = str(n)
  else:
    s = '{0:.2f}'.format(n)
  l = len(s)
  i = l-1;
  res = ''
  flag = 0
  k = 0
  while i>=0:
    if flag==0:
      res = res + s[i]
      if s[i]=='.':
        flag = 1
    elif flag==1:
      k = k + 1
      res = res + s[i]
      if k==3 and i-1>=0:
        res = res + ','
        flag = 2
        k = 0
    else:
      k = k + 1
      res = res + s[i]
      if k==2 and i-1>=0:
        res = res + ','
        flag = 2
        k = 0
    i = i - 1

  return res[::-1]

def main():
  n = 100.52
  print "INR " + currencyInIndiaFormat(n)  # INR 100.52
  n = 1000.108
  print "INR " + currencyInIndiaFormat(n)  # INR 1,000.108
  n = 1200000
  print "INR " + currencyInIndiaFormat(n)  # INR 12,00,000.00

main()

My Question: Is there a way to make my currencyInIndiaFormat function shorter, more concise and clean ? / Is there a better way to write my currencyInIndiaFormat function ?

Note: My question is mainly based on Python implementation of the above stated problem. It is not a duplicate of previously asked questions regarding conversion of currency to Indian format.

Indian Currency Format:

For example, numbers here are represented as:

1
10
100
1,000
10,000
1,00,000
10,00,000
1,00,00,000
10,00,00,000

Refer Indian Numbering System

Answer 1

Too much work.

>>> import locale
>>> locale.setlocale(locale.LC_MONETARY, 'en_IN')
'en_IN'
>>> print(locale.currency(100.52, grouping=True))
? 100.52
>>> print(locale.currency(1000.108, grouping=True))
? 1,000.11
>>> print(locale.currency(1200000, grouping=True))
? 12,00,000.00