You can select half of the elements in pure CSS... up to a point.
The only drawback is that you've to know the maximum number of total items. Could be 150 but it would then not work with 151.
Here's a demo: http://jsfiddle.net/tcK3F/ (*)
Minimal CSS:
/* selecting half or more items. Up to 6 */
li:first-child:last-child,
li:nth-child(n+2):nth-last-child(-n+2),
li:nth-child(n+3):nth-last-child(-n+3),
li:nth-child(n+4):nth-last-child(-n+4),
li:nth-child(n+5):nth-last-child(-n+5),
li:nth-child(n+6):nth-last-child(-n+6) {
color: white;
background: darkblue;
}
/* selecting half or less items. Up to 6 */
li:nth-child(n+2):last-child,
li:nth-child(n+3):nth-last-child(-n+2),
li:nth-child(n+4):nth-last-child(-n+3),
li:nth-child(n+5):nth-last-child(-n+4),
li:nth-child(n+6):nth-last-child(-n+5),
li:nth-child(n+7):nth-last-child(-n+6){
font-style: italic;
border: 2px solid red;
}
Based on an idea from:
The trick is from André Luís and seen in a post from Lea Verou: Styling elements based on sibling count. I adapted it to your need of a split selection.
Quick explanation:
:nth-last-child(-n+3)
will select the 3 last items from a parent; :nth-child(n+3)
will select all items except the first 3 ones. Combine them and you can select elements in pure CSS based on what follow them (or how many children are in a parent). Except you'll have to combine 75 of them with 74 commas if you want this trick to work with 150 elements... :)
Compatibility is IE9+ (JS polyfills exist)
(*)
first part of HTML code: even number of list items;
second part: odd number of list items
first CSS rule: will select last N from 2N items or last N+1/2 items from 2N+1 and style them in white on blue (ex: 3 items in a total of 5 or 6).
second CSS rule: will select last N from 2N items or last N-1/2 items from 2N+1 and style them with red border and italic (ex: 2 items in a total of 4 or 5)
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