Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
494 views
in Technique[技术] by (71.8m points)

jquery - Callback to .delay()

I have an $image that I .fadeIn and .fadeOut, and then .remove after .fadeOut completes. This is my code:

$image
   .fadeIn()
   .fadeOut(function() {
      $(this).remove();
   });

I want to add a .delay after .fadeOut, and .remove the $image only once .delay has completed. I have tried:

$image
   .fadeIn()
   .fadeOut()
   .delay(1000, function() {
      $(this).remove();
   });

The problem is that .delay doest not accept a callback function. How can I .remove the picture as a callback to .delay?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can use the queue() method to schedule your own function to run after delay() completes:

$image.fadeIn()
      .fadeOut()
      .delay(1000)
      .queue(function(next) {
          $(this).remove();
          next();
      });

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...