makefile - GNU Make pattern to build output in different directory than src

Question

I'm trying to create a Makefile which places my .o files in a different directory than my source files. I'm trying to use a pattern rule so I don't have to create identical rules for each source & object file.

My project structure looks something like:

project/
 + Makefile
 + src/
   + main.cpp
   + video.cpp
 + Debug/
   + src/       [contents built via Makefile:]
     + main.o
     + video.o

My Makefile looks something like:

OBJDIR_DEBUG = Debug
OBJ_DEBUG = $(OBJDIR_DEBUG)/src/main.o $(OBJDIR_DEBUG)/src/video.o

all: $(OBJ_DEBUG)

$(OBJ_DEBUG): %.o: %.cpp
    $(CXX) $(CFLAGS_DEBUG) $(INC_DEBUG) -c $< -o $@

This doesn't work, because it looks for my source files at Debug/src/*.cpp.

I've tried the following:

# Broken: make: *** No rule to make target `Debug/src/main.cpp', needed by `Debug/src/main.o'.  Stop.
# As a test, works if I change "%.cpp" to "Debug/src/main.cpp", though it obv. builds the wrong thing

# Strip OBJDIR_DEBUG from the start of source files
$(OBJ_DEBUG): %.o: $(patsubst $(OBJDIR_DEBUG)/%,%,%.cpp)
    $(CXX) $(CFLAGS_DEBUG) $(INC_DEBUG) -c $< -o $@

# Broken:
#   Makefile:70: target `src/main.o' doesn't match the target pattern
#   Makefile:70: target `src/video.o' doesn't match the target pattern

# Add OBJDIR_DEBUG in target rule
OBJ = src/main.o src/video.o

$(OBJ): $(OBJDIR_DEBUG)/%.o: %.cpp
    $(CXX) $(CFLAGS_DEBUG) $(INC_DEBUG) -c $< -o $@

Answer 1

After re-reading the documentation on static pattern rules, I derived the following pattern rule which seems to work.

$(OBJ_DEBUG): $(OBJDIR_DEBUG)/%.o: %.cpp
    $(CXX) $(CFLAGS_DEBUG) $(INC_DEBUG) -c $< -o $@

I'm not sure this is the best approach, and I'm open to suggestions.