Versioning of shared objects works as follows:
When you create a shared object, you give it both a real name and an soname
. These are used to install the shared object (which creates both the object and a link to it).
So you can end up with the situation:
pax> ls -al xyz*
-rw-r--r-- 1 pax paxgroup 12345 Nov 18 2009 xyz.so.1.5
lrwxrwxrwx 1 pax paxgroup 0 Nov 18 2009 xyz.so.1 -> xyz.so.1.5
lrwxrwxrwx 1 pax paxgroup 0 Nov 18 2009 xyz.so -> xyz.so.1
with xyz.so.1.5
possessing the SONAME
of xyz.so.1
.
When the linker links in xyz.so
, it follows the links all the way to xyz.so.1.5
and uses its SONAME
of xyz.so.1
to store in the executable. Then, when you run the executable, it tries to load xyz.so.1
which will point to a specific xyz.so.1.N
(not necessarily version 1.5).
So you could install xyz.so.1.6
and update the xyz.so.1
link to point to it instead and already-linked executables would use that instead.
One advantage of this multi-layer method is that you can have multiple potentially incompatible libraries of the same name (xyz.so.1.*
, xyz.so.2.*
) but, within each major version, you can freely upgrade them since they're supposed to be compatible.
When you link new executables:
- Those linking with
xyz.so
will get the latest minor version of the latest major version.
- Others linking with
xyz.so.1
will get the latest minor version of a specific major version.
- Still others linking with
xyz.so.1.2
will get a specific minor version of a specific major version.
Now keep that last paragraph in mind as we examine your comment:
Now lets say I compile another version of the same library with the following real-name, libmy.so.2.0
. The SONAME by guidelines would be libmy.so.2.0
.
No, I don't believe so. The soname
would be more likely to be libmy.so.2
so that you can make minor updates to the 2.x
stream and get the latest behaviour.
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