html - CSS: How can I set image size relative to parent height?

Question

I am trying to figure out how to re-size an image so that it keeps it ratio of width to height, but gets re-sized until the height of the image matches the height of the containing div. I have these images that are pretty large and long (screenshots), and I want to put them into a 200px width, 180px height div for display and without re-sizing the images manually. To make this look good, the sides of the image need to overflow and be hidden with the containing div. This is what I have so far:

http://jsfiddle.net/f9krj/2/

HTML

<a class="image_container" href="http://www.skintype.ca/assets/background-x_large.jpg">
    <img src="http://www.skintype.ca/assets/background-x_large.jpg" alt="" />
</a>

CSS

a.image_container {
    background-color: #999;
    width: 200px;
    height: 180px;
    display: inline-block;
    overflow: hidden;
}
a.image_container img {
    width: 100%;
}

As you can see, there is grey color showing on the images parent container which should not be shown at all. In order for that container to be filled completely, the width needs to be overflowed equally on both sides. Is this possible? Is it also possible to account for an image that is also too tall?

Answer 1

Original Answer:

If you are ready to opt for CSS3, you can use css3 translate property. Resize based on whatever is bigger. If your height is bigger and width is smaller than container, width will be stretch to 100% and height will be trimmed from both side. Same goes for larger width as well.

Your need, HTML:

<div class="img-wrap">
  <img src="http://lorempixel.com/300/160/nature/" />
</div>
<div class="img-wrap">
  <img src="http://lorempixel.com/300/200/nature/" />
</div>
<div class="img-wrap">
  <img src="http://lorempixel.com/200/300/nature/" />
</div>

And CSS:

.img-wrap {
  width: 200px;
  height: 150px;
  position: relative;
  display: inline-block;
  overflow: hidden;
  margin: 0;
}

div > img {
  display: block;
  position: absolute;
  top: 50%;
  left: 50%;
  min-height: 100%;
  min-width: 100%;
  transform: translate(-50%, -50%);
}

Voila! Working: http://jsfiddle.net/shekhardesigner/aYrhG/

Explanation

DIV is set to the relative position. This means all the child elements will get the starting coordinates (origins) from where this DIV starts.

The image is set as a BLOCK element, min-width/height both set to 100% means to resize the image no matter of its size to be the minimum of 100% of it's parent. min is the key. If by min-height, the image height exceeded the parent's height, no problem. It will look for if min-width and try to set the minimum height to be 100% of parents. Both goes vice-versa. This ensures there are no gaps around the div but image is always bit bigger and gets trimmed by overflow:hidden;

Now image, this is set to an absolute position with left:50% and top:50%. Means push the image 50% from the top and left making sure the origin is taken from DIV. Left/Top units are measured from the parent.

Magic moment:

transform: translate(-50%, -50%);

Now, this translate function of CSS3 transform property moves/repositions an element in question. This property deals with the applied element hence the values (x, y) OR (-50%, -50%) means to move the image negative left by 50% of image size and move to the negative top by 50% of image size.

Eg. if Image size was 200px × 150px, transform:translate(-50%, -50%) will calculated to translate(-100px, -75px). % unit helps when we have various size of image.

This is just a tricky way to figure out centroid of the image and the parent DIV and match them.

Apologies for taking too long to explain!

Resources to read more:

• https://developer.mozilla.org/en-US/docs/Web/CSS/transform-function/translate
• https://css-tricks.com/centering-css-complete-guide/