Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
764 views
in Technique[技术] by (71.8m points)

prolog - Intersection and union of 2 lists

i'm starting up learning prolog (i use SWI-prolog) and i did a simple exercise in which i have 2 lists and i want to calculate their intersection and union. Here is my code that works pretty well but i was asking myself if there is a better way to do it as i don't like to use the CUT operator.

intersectionTR(_, [], []).
intersectionTR([], _, []).
intersectionTR([H1|T1], L2, [H1|L]):-
    member(H1, L2),
    intersectionTR(T1, L2, L), !.
intersectionTR([_|T1], L2, L):-
    intersectionTR(T1, L2, L).

intersection(L1, L2):-
    intersectionTR(L1, L2, L),
    write(L).


unionTR([], [], []).
unionTR([], [H2|T2], [H2|L]):-
    intersectionTR(T2, L, Res),
    Res = [],
    unionTR([], T2, L),
    !.
unionTR([], [_|T2], L):-
    unionTR([], T2, L),
    !.

unionTR([H1|T1], L2, L):-
    intersectionTR([H1], L, Res),
    Res = [],
    unionTR(T1, L2, L).
unionTR([H1|T1], L2, [H1|L]):-
    unionTR(T1, L2, L).

union(L1, L2):-
    unionTR(L1, L2, L),
    write(L).

Keep in mind that i want to have just 1 result, not multiple results (even if correct) so running the code with this:

?- intersect([1,3,5,2,4] ,[6,1,2]).

should exit with:

[1,2]
true.

and not with

[1,2]
true ;
[1,2]
true ;
etc...

The same must be valid for union predicate.
As i said my code works pretty well but please suggest better ways to do it.
Thanks

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Also, not sure why you're dead against cuts, so long as their removal would not change the declaritive meaning of the code, as per your link. For example:

inter([], _, []).

inter([H1|T1], L2, [H1|Res]) :-
    member(H1, L2),
    inter(T1, L2, Res).

inter([_|T1], L2, Res) :-
    inter(T1, L2, Res).

test(X):-
        inter([1,3,5,2,4], [6,1,2], X), !.

test(X).
X = [1, 2].

In the test bit where I call the code, I'm just saying do the intersection but I'm only interested in the first answer. There are no cuts in the predicate definitions themselves.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...