Assuming that $z0
is a register which always contains the number zero.
Then the MIPS instruction OR $t0, $t1, $t2
puts the bitwise OR
of $t1
and $t2
into the register $t0
.
Suppose that the register $t2
contains the number "5". What is in the register $t0
after the execution of the instruction or $t0, $z0, $t1
This was a question in a mock exam paper but I'm confused as to how to work it out. I really need help please. How would I go about solving it? I'm having trouble figuring out the value of t1 I know how bitwise OR works
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