I think you have mixed up index numbers with keys.
Dictionaries are formed like such:
{key: value}
data.keys()
will return a list of keys.
In your case:
data.keys()
[0,1,2]
From there, you can call the first item, which is 0 (First item in a list is 0, and then progresses by one).
data.keys()[0]
0
If you are looking for a specific key by the predefined values, then try:
x = 'GAME_ID'
y = '0021600457'
for index_num, sub_dict in data.items():
for eachsub_keys in sub_dict.keys():
if eachsub_keys == x:
print(index_num)
for index_num, sub_dict in data.items():
for eachsub_values in sub_dict.values():
if eachsub_values == y:
print(index_num)
Output:
0
1
2
0
1
2
Note: python3 no longer uses .iteritems()
By the way, you are missing a curly brace at the end. It should be like this:
data = {0: {'GAME_ID': '0021600457', 'TEAM_ID': '1610612744'}, 1: {'GAME_ID':
'0021600457', 'TEAM_ID': '1610612744'}, 2: {'GAME_ID': '0021600457', 'TEAM_ID':
'1610612744'}}
Assuming that you wanted consistency, I've added the missing quotes as well.
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