Hope you can help me to understand how I can find out the six numbers. Have tried couple set of numbers that I thought was the right ones but guess I′m not understanding it right.
So for the first, this six numbers that I'm looking for, isn′t it numbers that are the outcome or the number that I put in to fit to the code?
Do I have to go through all the code or are there just few lines that I can find out these numbers? Started to think that I'm over thinking it, that it′s much easier to find those numbers then the ways I′m trying.
08048b74 <phase_2>:
8048b74: 53 push %ebx
8048b75: 83 ec 38 sub $0x38,%esp
8048b78: 8d 44 24 18 lea 0x18(%esp),%eax
8048b7c: 89 44 24 04 mov %eax,0x4(%esp)
8048b80: 8b 44 24 40 mov 0x40(%esp),%eax
8048b84: 89 04 24 mov %eax,(%esp)
8048b87: e8 28 07 00 00 call 80492b4 <read_six_numbers>
8048b8c: 83 7c 24 18 00 cmpl $0x0,0x18(%esp)
8048b91: 79 22 jns 8048bb5 <phase_2+0x41>
8048b93: e8 dd 06 00 00 call 8049275 <explode_bomb>
8048b98: eb 1b jmp 8048bb5 <phase_2+0x41>
8048b9a: 89 d8 mov %ebx,%eax
8048b9c: 03 44 9c 14 add 0x14(%esp,%ebx,4),%eax
8048ba0: 39 44 9c 18 cmp %eax,0x18(%esp,%ebx,4)
8048ba4: 74 05 je 8048bab <phase_2+0x37>
8048ba6: e8 ca 06 00 00 call 8049275 <explode_bomb>
8048bab: 83 c3 01 add $0x1,%ebx
8048bae: 83 fb 06 cmp $0x6,%ebx
8048bb1: 75 e7 jne 8048b9a <phase_2+0x26>
8048bb3: eb 07 jmp 8048bbc <phase_2+0x48>
8048bb5: bb 01 00 00 00 mov $0x1,%ebx
8048bba: eb de jmp 8048b9a <phase_2+0x26>
8048bbc: 83 c4 38 add $0x38,%esp
8048bbf: 5b pop %ebx
8048bc0: c3 ret
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