Using the functions such as lambdas, range, map, filter and reduce/fold, calculate the sum of numbers between 1 and 1000 which are divisible by 5 or 3 and print the result.
We can do the following:
println((1..1000).filter{ it % 3 == 0 || it % 5 == 0 }.reduce{sum, element -> sum + element})
Instead of reduce we could use sum as well which would look like this:
sum
println((1..1000).filter{ it % 3 == 0 || it % 5 == 0 }.sum())
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