javascript - Count string occurrence and replace with string and count - JS

Question

I have a use case where I have a string with the same substring if followed continuously should return the string and count together. If not, it should return the same string. We need to check for only one value here, in the below use case it is 'transfer'. Should be case insensitive. I do not care if the string 'Name' occurs more than once.

Example:

String is 'Name transfer transfer transfer transfertranfser' should return 'Name transfer 5' as 5 is the length of transfer. String is 'Name transfer Transfer transfer TransferTranfser' should return 'Name transfer 5' as 5 is the length of transfer. String is 'Name transfer name transfer' should return 'Name transfer name transfer' as transfer is not continous.

Please advice.

var temp = "Model transfer transfer transfer transfertransfer";
var count = (temp.match(/transfer/g) || []).length;
let abc;
if (count > 1) {
  abc = temp.replace('transfer', `transfer ${count}`)
}
console.log(count);
console.log(abc)

Answer 1

Use this:

var temp = "Model transfer transfer transfer transfertransfer";
var count = (temp.match(/transfer/ig) || []).length;
let abc;
if (count > 1) {
  abc = temp.replace(/[s]*transfer[s]*/ig, '').concat(` transfer ${count}`);
}
console.log(count);
console.log(abc)

This way you are replacing all "transfer" string with additional whitespaces. Mind the g flag in the replace regex as otherwise Javascript will only replace the first occurrence.