c - Remove trailing NULL terminator

Question

I have a large char array that is filled with 0's. I read an incoming file from a socket and place it's contents in the buffer. I can't write the buffer with all of the ''s in it, so I allocate a new buffer with the correct size and to write. I used this approach to do that:

int i = 0;
while(buf[i] != ''){
    i++;
}
char new[i];
while(i){
    new[i] = buf[i];
    i--;
}
new[0] = buf[0];

While this approach works, it doesn't seem like the smartest or most elegant way. What is the best way to remove all of the trailing NULL chars from a char array?

Answer 1

I suppose easier way to do this is:

size_t len = strlen(buf); // will calculate number of non-0 symbols before first 0
char * newBuf = (char *)malloc(len); // allocate memory for new array, don't forget to free it later
memcpy(newBuf, buf, len); // copy data from old buf to new one