So what i need is basically described in the subject.
Like if i would put in number 12 and amount of parts it should devide into, i would like it to return something like (with 4 parts) 8, 2, 1, 1. But not doubles because i need the values as int.
I had found one answer earlier but it only worked using doubles. not ints.
(this is the one i found)
public double[] divideUniformlyRandomly(double number, int part) {
double uniformRandoms[] = new double[part];
Random random = new Random();
double mean = number / part;
double sum = 0.0;
for (int i=0; i<part / 2; i++) {
uniformRandoms[i] = random.nextDouble() * mean;
uniformRandoms[part - i - 1] = mean + random.nextDouble() * mean;
sum += uniformRandoms[i] + uniformRandoms[part - i -1];
}
uniformRandoms[(int)Math.ceil(part/2)] = uniformRandoms[(int)Math.ceil(part/2)] + number - sum;
return uniformRandoms;
I had tried changing this code to work using Ints by doing this:
public int[] divide(int number) {
int part = getDivider(number);
int uniformRandoms[] = new int[part];
Random random = new Random();
int mean = number / part;
int sum = 0;
for (int i=0; i<part / 2; i++) {
uniformRandoms[i] = random.nextInt() * mean;
uniformRandoms[part - i - 1] = mean + random.nextInt() * mean;
sum += uniformRandoms[i] + uniformRandoms[part - i -1];
}
uniformRandoms[(int)Math.round(part/2)] = uniformRandoms[(int)Math.round(part/2)] + number - sum;
for(int i : uniformRandoms)
System.out.println(i);
return uniformRandoms;
}
But when running that using number: 512 and using 10 parts (getDivider() will return 10) itll output this:
-1058809647, -2102647561, 469849949, 1627965716, -290084223, -33347991
And alot more of this kind of numbers.
Thanks.
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