python 3.x - Find and print vowels from a string using a while loop

Question

Study assignment (using python 3):

For a study assignment I need to write a program that prints the indices of all vowels in a string, preferably using a 'while-loop'. So far I have managed to design a 'for-loop' to get the job done, but I could surely need some help on the 'while-loop'

for-loop solution:

string = input( "Typ in a string: " )
vowels = "a", "e", "i", "o", "u"
indices = ""

for i in string:
    if i in vowels:
        indices += i
print( indices )

while-loop solution:

string = input( "Typ in a string: " )
vowels = "a", "e", "i", "o", "u"
indices = ""

while i < len( string ):
    <code>
    i += 1
print( indices )

Would the use 'index()' or 'find()' work here?

Answer 1

Try This :

   string = input( "Typ in a string: " )
    vowels = ["a", "e", "i", "o", "u"]




        higher_bound=1
        lower_bound=0

        while lower_bound<higher_bound:
            convert_str=list(string)
            find_vowel=list(set(vowels).intersection(convert_str))
            print("Vowels in {} are {}".format(string,"".join(find_vowel)))

            lower_bound+=1

You can also set higher_bound to len(string) then it will print result as many times as len of string.

Since this is your Study assignment you should look and practice yourself instead of copy paste. Here is additional info for solution :

In mathematics, the intersection A ∩ B of two sets A and B is the set that contains all elements of A that also belong to B (or equivalently, all elements of B that also belong to A), but no other elements. For explanation of the symbols used in this article, refer to the table of mathematical symbols.

In python :

The syntax of intersection() in Python is:

A.intersection(*other_sets)

A = {2, 3, 5, 4}
B = {2, 5, 100}
C = {2, 3, 8, 9, 10}

print(B.intersection(A))
print(B.intersection(C))
print(A.intersection(C))
print(C.intersection(A, B))