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sql server - Order by two columns with usage of CASE WHEN

I have a query like this:

SELECT 
    ROW_NUMBER() OVER(ORDER BY USER_FNM, USER_LNM) AS ROW_NUM,
    USER_TEL, USER_FAX, USER_MOB            
FROM 
    BAUSER      
ORDER BY            
    CASE 
       WHEN @cOrderBy = 'USER_FNM_USER_LNM ASC' THEN USER_LNM 
    END ASC,
    CASE 
       WHEN @cOrderBy = 'USER_FNM_USER_LNM DESC' THEN USER_LNM 
    END DESC,
    CASE 
       WHEN @cOrderBy IS NULL THEN USER_KEY 
    END ASC
    OFFSET @iStartIndex ROWS
    FETCH NEXT @iRowsPerPage ROWS ONLY

What I would like to do is sorting by two columns - but this is showing syntax error:

CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM ASC' THEN USER_LNM, USER_FNM END ASC

Any idea how to sort by two columns in this case?

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1 Answer

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CASE is an expression that returns a single expression/value. You need to write one CASE statement per column:

ORDER BY            
CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM ASC'        THEN USER_LNM END ASC,
CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM DESC'       THEN USER_LNM END DESC,
CASE WHEN @cOrderBy IS NULL                          THEN USER_KEY END ASC,

CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM ASC'        THEN USER_FNM END ASC,
CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM DESC'       THEN USER_FNM END DESC

Update (to reflect updated question)

Since you have ROW_NUM column, you can sort by that:

CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM ASC'        THEN ROW_NUM END ASC,
CASE WHEN @cOrderBy = 'USER_FNM_USER_LNM DESC'       THEN ROW_NUM END DESC,
CASE WHEN @cOrderBy IS NULL 

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