No such element exception in Selenium code using Java

Question

While i tried automating a website using selenium and Java i got no such element exception even though i got correct xpath while inspecting the field. After giving a city by sendkeys i tried to select 1st option from dropdown by select method and actions keyword but both didnt work and throwed exception. I will attach the code and image of inspected website.Kindly help with the issue

@Test
  public void abhibusHotel() throws Exception {
      driver.get("https://www.abhibus.com/");
      HomePage ohome=new HomePage(driver);
      ohome.hotelPage();
      HotelBooking obook=new HotelBooking(driver);
      obook.bookingDetails();
      Thread.sleep(2000);

public void bookingDetails()
    {
        try {
            wait.until(ExpectedConditions.visibilityOfElementLocated(city)).sendKeys("Bengaluru");
            //Select se=new Select(wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("(//span[text()='Beng'])[1]/parent::div"))));
            //Select se=new Select(wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//span[text()='Beng'][1]"))));

            //se.selectByIndex(1);
            WebElement tooltip= wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//span[text()='Beng']/parent::div")));
            oaction.moveToElement(tooltip).click().build().perform();
        }catch (Exception e) {
            // TODO: handle exception
            e.printStackTrace();
        }
        
    }

question from:https://stackoverflow.com/questions/66067923/no-such-element-exception-in-selenium-code-using-java

Answer 1

Your screenshot is saying that there are 9 matching elements. Selenium takes the first one. That first one is not necessarily visible. You need to narrow your xpath query so that it returns the only one that represents what is currently visible.