c - static variable changing value with no error displayed?

Question

(Closed.) This question is not reproducible or was caused by typos. It is not currently accepting answers. question from:https://stackoverflow.com/questions/66069047/static-variable-changing-value-with-no-error-displayed

Answer 1

For starters in the beginning of the program you changed the static variable b

b = b-1;

the keyword static does not have the meaning as the keyword const.

On the other hand, in this call of printf there is evidently a typo

printf("%d 
","%d",a,b);
               ^^^^

In fact you are trying to output a pointer to the string literal "%d" as an integer.

That is the function has four arguments and only one conversion specifier in the first argument.

The compiler could issue a warning that there are redundant arguments in the call of printf.

You could write for example like :)

printf("%d 
" "%d",a,b);

In this case the output would be

11
1

Because the above call is equivalent to

printf("%d 
%d",a,b);

But it seems you mean

printf("%d %d
", a, b);

So neither static variable is changed spontanno.