python - 删除，删除和弹出列表之间的区别(Difference between del, remove and pop on lists)

Question

>>> a=[1,2,3]
>>> a.remove(2)
>>> a
[1, 3]
>>> a=[1,2,3]
>>> del a[1]
>>> a
[1, 3]
>>> a= [1,2,3]
>>> a.pop(1)
2
>>> a
[1, 3]
>>> 

Is there any difference between the above three methods to remove an element from a list?

(以上三种从列表中删除元素的方法之间有什么区别吗？)

  ask by sachin irukula translate from so

Answer 1

Yes, remove removes the first matching value , not a specific index:

(是的， remove删除第一个匹配值 ，而不是特定索引：)

>>> a = [0, 2, 3, 2]
>>> a.remove(2)
>>> a
[0, 3, 2]

del removes the item at a specific index:

(del删除指定索引处的项目：)

>>> a = [3, 2, 2, 1]
>>> del a[1]
>>> a
[3, 2, 1]

and pop removes the item at a specific index and returns it.

(然后pop会删除指定索引处的项目并返回它。)

>>> a = [4, 3, 5]
>>> a.pop(1)
3
>>> a
[4, 5]

Their error modes are different too:

(它们的错误模式也不同：)

>>> a = [4, 5, 6]
>>> a.remove(7)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: list.remove(x): x not in list
>>> del a[7]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: list assignment index out of range
>>> a.pop(7)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: pop index out of range