javascript - 使用JavaScript / jQuery在重定向上发送POST数据？ [重复](Send POST data on redirect with JavaScript/jQuery? [duplicate])

Question

This question already has an answer here:(这个问题在这里已有答案：)

• JavaScript post request like a form submit 29 answers(JavaScript发布请求，如表单提交 29个答案)

Basically what I want to do is send POST data when I change the window.location , as if a user has submitted a form and it went to a new page.(基本上我想要做的是在我更改window.location时发送POST数据，就像用户提交了一个表单并进入新页面一样。)

I need to do it this way because I need to pass along a hidden URL, and I can't simply place it in the URL as a GET for cosmetic reasons.(我需要这样做，因为我需要传递一个隐藏的URL，而且出于美观的原因，我不能简单地将它作为GET放在URL中。)

This is what I have at the moment, but it doesn't send any POST data.(这就是我目前所拥有的，但它不会发送任何POST数据。)

if(user has not voted) {

    window.location = 'http://example.com/vote/' + Username;

}

I know that you can send POST data with jQuery.post() , but I need it to be sent with the new window.location .(我知道你可以用jQuery.post()发送POST数据，但我需要用新的window.location发送它。)

So to recap, I need to send api_url value via POST to http://example.com/vote/ , while sending the user to the same page at the same time.(所以回顾一下，我需要通过POST将api_url值发送到http://example.com/vote/ ，同时将用户同时发送到同一页面。)

---

For future reference, I ended up doing the following :(为了将来参考，我最终做了以下事情 ：)

if(user has not voted) {

    $('#inset_form').html('<form action="http://example.com/vote/' + Username + '" name="vote" method="post" style="display:none;"><input type="text" name="api_url" value="' + Return_URL + '" /></form>');

    document.forms['vote'].submit();

}

  ask by Josh Foskett translate from so

Answer 1

per @Kevin-Reid's answer, here's an alternative to the "I ended up doing the following" example that avoids needing to name and then lookup the form object again by constructing the form specifically (using jQuery)..(根据@ Kevin-Reid的回答，这里是“我最终做了以下”示例的替代方法，它避免了需要命名，然后通过专门构造表单（使用jQuery）再次查找表单对象。)

var url = 'http://example.com/vote/' + Username;
var form = $('<form action="' + url + '" method="post">' +
  '<input type="text" name="api_url" value="' + Return_URL + '" />' +
  '</form>');
$('body').append(form);
form.submit();