Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
853 views
in Technique[技术] by (71.8m points)

java - Why is myString.equals("aString"); different from "aString".equals(myString);?

I heard several times that in using boolean equals(Object o) to compare Strings, it's better to put the constant on the left side of the function as in the following:

  • Bad: myString.equals("aString");
  • Good: "aString".equals(myString);

Why is this?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Because if myString is null you get an exception. You know "aString" will never be null, so you can avoid that problem.

Often you'll see libraries that use nullSafeEquals(myString,"aString"); everywhere to avoid exactly that (since most times you compare objects, they aren't generated by the compiler!)


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...