sql server - Split IPv4 address into 4 numbers in Oracle sql

Question

I'm trying to split a given IPv4 address into four numbers.

In SQL Server this query works well for me:

select CAST (PARSENAME('10.20.30.40',4) AS INT) 

result: 10

select CAST (PARSENAME('10.20.30.40',3) AS INT)

result: 20

and so on.

I need the equivalent syntax in Oracle SQL, but can't find it. Any idea?

Answer 1

You could use regexp_substr:

select ip,
       regexp_substr(ip, 'd+',1,1) as first_octet,
       regexp_substr(ip, 'd+',1,2) as second_octet,
       regexp_substr(ip, 'd+',1,3) as third_octet,
       regexp_substr(ip, 'd+',1,4) as fourth_octet
from  (select '10.20.30.40' AS ip from dual )ips;

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