It sounds like you want to upload a file to your Azure Function with Http Trigger in Java via a HTML form with multipart/form-data
like below.
<form method="POST" enctype="multipart/form-data" action="https://<your function app>/api/HttpTrigger-Java">
File to upload: <input type="file" name="upfile"><br/>
Notes about the file: <input type="text" name="note"><br/>
<br/>
<input type="submit" value="Press"> to upload the file!
</form>
However, there is not any class implements the interface HttpRequestMessage<T>
and seems to not cast HttpRequestMessage
to HttpServletRequest
after I researched the source code of GitHub Repo Azure/azure-functions-java-library
.
Per my experience, the only way is to parse the header and body of a multipart/form-data
request to get the file. There is an answer of the similar SO thread Library and examples of parsing multipart/form-data from inputstream posted by the question owner, which includes the code using MultipartStream
class of Apache Commons FileUpload that works after I test it.
Here is the Content-Type
header and body of a multipart/form-data
request received from Azure Function for Java.
Header Content-Type
content-type: multipart/form-data; boundary=----WebKitFormBoundaryT2TWuevX3RIYWRQF
multipart/form-data
request body
------WebKitFormBoundaryT2TWuevX3RIYWRQF
Content-Disposition: form-data; name="upfile"; filename="z.txt"
Content-Type: text/plain
1234
ABCD
------WebKitFormBoundaryT2TWuevX3RIYWRQF
Content-Disposition: form-data; name="note"
test.txt
------WebKitFormBoundaryT2TWuevX3RIYWRQF--
Here is my sample code to fetch the file.
@FunctionName("HttpTrigger-Java")
public HttpResponseMessage run(
@HttpTrigger(name = "req", methods = {HttpMethod.GET, HttpMethod.POST}, authLevel = AuthorizationLevel.ANONYMOUS) HttpRequestMessage<Optional<String>> request,
final ExecutionContext context) {
String contentType = request.getHeaders().get("content-type"); // Get content-type header
// here the "content-type" must be lower-case
String body = request.getBody().get(); // Get request body
InputStream in = new ByteArrayInputStream(body.getBytes()); // Convert body to an input stream
String boundary = contentType.split(";")[1].split("=")[1]; // Get boundary from content-type header
int bufSize = 1024;
MultipartStream multipartStream = new MultipartStream(in, boundary.getBytes(), bufSize, null); // Using MultipartStream to parse body input stream
// the code below comes from the SO thread above
// you can fetch a file content from readBodyData
// after the headers Content-Disposition: form-data; name="upfile"; filename="test.txt"
Content-Type: text/plain
boolean nextPart = multipartStream.skipPreamble();
while (nextPart) {
String header = multipartStream.readHeaders();
System.out.println("");
System.out.println("Headers:");
System.out.println(header);
System.out.println("Body:");
multipartStream.readBodyData(System.out);
System.out.println("");
nextPart = multipartStream.readBoundary();
}
return request.createResponseBuilder(HttpStatus.OK).body("Success").build();
}
The output of code above in terminal :
Headers:
Content-Disposition: form-data; name="upfile"; filename="test.txt"
Content-Type: text/plain
Body:
1234
ABCD
Headers:
Content-Disposition: form-data; name="note"
Body:
test.txt
Update: If upload an image, the output of the code above is like below.
Headers:
Content-Disposition: form-data; name="upfile"; filename="test.jpg"
Content-Type: image/png
Body:
<the binary content of an image>
So you can parse the header to get the filename
value to use FileOutputStream
to store it, as the code below.
while(nextPart) {
String header = multipartStream.readHeaders();
System.out.println("");
System.out.println("Headers:");
System.out.println(header);
System.out.println("Body:");
if (header.contains("Content-Type: image/")) {
int start = header.indexOf("filename=")+"filename=".length()+1;
int end = header.indexOf("
")-1;
String filename = header.substring(start, end);
System.out.println(filename);
FileOutputStream fos = new FileOutputStream(filename);
multipartStream.readBodyData(fos);
} else {
multipartStream.readBodyData(System.out);
}
System.out.println("");
nextPart = multipartStream.readBoundary();
}
Update 2:
I discovered there seems to be an issue of Azure Function for Java which may be a bug that will lose some bytes when uploading binary file, but it will not happend for uploading text file. So a workaround solution is to convert upload file to base64 string in browser to post to Azure Function and convert base64 content uploaded to the origin binary file in Azure Function.
Here is my testing HTML code.
File to upload: <input type="file" name="upfile" id="fileup"><br/>
<form method="POST" enctype="multipart/form-data" action="http://localhost:7071/api/HttpTrigger-Java">
Notes about the file: <input type="text" name="note"><br/>
<input type="hidden" name="file_base64" id="file_base64"><br/>
<input type="submit" value="Press"> to upload the file!
</form>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js">/script>
<script>
$(document).ready(function(){
$("#fileup").change(function(){
var v = $(this).val();
var reader = new FileReader();
reader.readAsDataURL(this.files[0]);
reader.onload = function(e){
console.log(e.target.result);
$('#file_base64').val(e.target.result);
};
});
});
</script>
The form above will post the header and body of base64 file chunk as below.
Header:
Content-Disposition: form-data; name="file_base64"
Body:
data:image/jpg;base64,iVBORw0KGgoAAAANSUhEUgAAB.............
My Java code in Azure Function:
import java.io.ByteArrayOutputStream;
import java.util.Base64;
if (header.equals("Content-Disposition: form-data; name="file_base64"")) {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
multipartStream.readBodyData(baos);
String content = baos.toString();
// System.out.println(content);
int index = content.indexOf(",")+1; // Get the index of base64 string in data-uploaded string
byte[] imgBytes = Base64.getDecoder().decode(content.substring(index)); // convert image base64 string to image byte arrays
....
// To upload image byte array to Blob Storage
// You can get the upload image filename from the form input `note`, please notes the order of form input elements.
} else {
multipartStream.readBodyData(System.out);
}